Los Angeles Lakers 1988 Championship - The Playoffs

The 1988 NBA Playoffs: Los Angeles Lakers and all the other teams

Here you have the information about the 1988 NBA Playoffs and the path the Los Angeles Lakers took to win a new championship. The league had 23 teams in 1988 and the best 16 (8 from each Conference) competed in a traditional playoff format.

Western Conference						NBA Finals	Eastern Conference
(1) Lakers	3										3	Celtics (1)
		Lakers	4						4	Boston
(8) Spurs	0										1	Knicks (8)
				Lakers	4		2	Boston
(4) Blazers	1										3	Hawks (4)
		Jazz	3						3	Hawks
(5) Jazz	3					Lakers	4				2	Bucks (5)
					L.A. Lakers Champion
(2) Nuggets	3					Pistons	3				3	Pistons (2)
		Nuggets	2						4	Pistons
(7) Sonics	2										2	Bullets (7)
				Mavs	3		4	Pistons
(3) Mavs	3										3	Bulls (3)
		Mavs	4						1	Bulls
(6) Rockets	1										2	Cavaliers (6)

Western Conference teams:

Lakers = Los Angeles Lakers
Spurs = San Antonio Spurs
Blazers = Portland Trail Blazers
Jazz = Utah Jazz
Nuggets = Denver Nuggets
Sonics = Seattle Supersonics
Mavs = Dallas Mavericks
Rockets = Houston Rockets

Eastern Conference teams:

Celtics = Boston Celtics
Knicks = New York Knicks
Hawks = Atlanta Hawks
Bucks = Milwaukee Bucks
Pistons = Detroit Pistons
Bullets = Washington Bullets
Bulls = Chicago Bulls
Cavaliers = Cleveland Cavaliers

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